AP EAMCET · PHYSICS · Motion In One Dimension
A person of \(60 \mathrm{~kg}\) mass is in a lift which is coming down such that the man exerts a force of \(150 \mathrm{~N}\) on the floor of the lift. Then the acceleration of the lift is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)
- A \(7.5 \mathrm{~ms}^{-2}\)
- B \(40.0 \mathrm{~ms}^{-2}\)
- C \(22.5 \mathrm{~ms}^{-2}\)
- D \(15.0 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(A) \(7.5 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
Here \(g_{e f f}=g-a\) So, \(m(g-a)=150 \mathrm{~N}\) \(60(10-a)=150\) \(a=7.5 \mathrm{~m} / \mathrm{s}^2\)
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