AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A soccer ball of mass 250 g is moving horizontally to the left with a speed \(22 \mathrm{~ms}^{-1}\). This ball is kicked towards right with a velocity \(30 \mathrm{~ms}^{-1}\) at an angle \(53^{\circ}\) with the horizontal in upward direction. Assuming that it took 0.01 s for the collision to take place, the average force acting is \(\left(\cos 53^{\circ}=\frac{3}{5} ; \sin 53^{\circ}=\frac{4}{5}\right)\)
- A 1000 N
- B 986 N
- C 1166 N
- D 2000 N
Answer & Solution
Correct Answer
(C) 1166 N
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{t}=0.01 \mathrm{~s}\) Change in momentum,…
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