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AP EAMCET · Maths · Circle

The equations of the tangent to the circle \(5 x^2+5 y^2=1\) parallel to the line \(3 x+4 y=1\) are

  1. A \(3 x+4 y= \pm 2 \sqrt{5}\)
  2. B \(3 x+4 y= \pm \sqrt{5}\)
  3. C \(6 x+8 y= \pm \sqrt{5}\)
  4. D \(3 x+4 y= \pm 3 \sqrt{5}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3 x+4 y= \pm \sqrt{5}\)

Step-by-step Solution

Detailed explanation

Given, equation of circle is \(5 x^2+5 y^2=1\) \(\begin{aligned} & \Rightarrow \quad x^2+y^2=(1 / \sqrt{5})^2 \\ & \therefore \text { Centre }=(0,0) \text { and radius }=1 / \sqrt{5}\end{aligned}\) Given, line is 3x + 4y = 1 \[ \Rightarrow \text { Slope }(m)=\frac{-3}{4} \]…