AP EAMCET · PHYSICS · Magnetic Effects of Current
A sample of a paramagnetic salt containing \(3 \times 10^{24}\) atomic dipoles each of dipole moment \(2 \times 10^{-23} \quad \mathrm{~A}-\mathrm{m}^2\) is subjected to a uniform magnetic field of \(880 \mathrm{mT}\) and cooled to a temperature of \(3.5 \mathrm{~K}\). The degree of magnetic saturation achieved is \(10 \%\). If the sample is subjected to a magnetic field of \(990 \mathrm{mT}\) and cooled to a temperature of \(2.1 \mathrm{~K}\), then the total dipole moment of the sample is
- A \(11.25 \mathrm{~A}-\mathrm{m}^2\)
- B \(23.5 \mathrm{~A}-\mathrm{m}^2\)
- C \(15 \mathrm{~A}-\mathrm{m}^2\)
- D \(75 \mathrm{~A}-\mathrm{m}^2\)
Answer & Solution
Correct Answer
(A) \(11.25 \mathrm{~A}-\mathrm{m}^2\)
Step-by-step Solution
Detailed explanation
Initially total dipole moment of sample \[ =3 \times 10^{24} \times 2 \times 10^{-23} \times \frac{10}{100}=6 \mathrm{JT}^{-1} \] From Curie's law, \(m \propto \frac{B}{T}\), we get…
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