AP EAMCET · PHYSICS · Oscillations
The displacement of a particle executing simple harmonic motion is \(y=\mathrm{A} \sin (2 \mathrm{t}+\phi) m\), where \(t\) is time in second and \(\phi\) is phase angle. At time \(t=0\), the displacement and velocity of the particle are 2 m and \(4 \mathrm{~ms}^{-1}\). The phase angle, \(\phi=\)
- A \(60^{\circ}\)
- B \(30^{\circ}\)
- C \(45^{\circ}\)
- D \(90^{\circ}\)
Answer & Solution
Correct Answer
(C) \(45^{\circ}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text {For } S H M, y=A \sin (2 t+\phi) \\ \therefore & v=2 A \cos (2 t+\phi) \\ \text {At } & t=0, y=2 m, v=4 ms^{-1}\end{aligned}\) \(\therefore 2=a \sin (2 \times 0+\phi) \Rightarrow \sin \phi=\frac{2}{A}...(i)\) Also,…
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