AP EAMCET · Chemistry · Solid State
The anions (A) of \(\mathrm{C}_{\mathrm{p}} \mathrm{A}_{\mathrm{q}}\) molecule forms an fcc lattice. Cations (C) are positioned at the body center and half of the edge centers. The formula of the molecule is
- A \(\mathrm{CA}\)
- B \(\mathrm{CA}_2\)
- C \(\mathrm{C}_3 \mathrm{~A}_4\)
- D \(\mathrm{C}_5 \mathrm{~A}_8\)
Answer & Solution
Correct Answer
(D) \(\mathrm{C}_5 \mathrm{~A}_8\)
Step-by-step Solution
Detailed explanation
In a unit cell of fcc lattice, \(A\) is present at 8 corners and 6 faces. \(\therefore \quad\) Effective no. of \({ }^{\prime} \mathrm{A}^{\prime}=\frac{1}{8} \times 8+\frac{1}{2} \times 6=4\) \(\mathrm{C}\) is present at body centre and 6 edges. \(\therefore \quad\) Effective…
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