AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A ball falls freely from rest from a height of 6.25 m on to a hard horizontal surface. If the ball reaches a height of 81 cm after second bounce from the surface, the coefficient of restitution is
- A 0.3
- B 0.45
- C 0.75
- D 0.6
Answer & Solution
Correct Answer
(D) 0.6
Step-by-step Solution
Detailed explanation
From the figure, \(\begin{aligned} & u=\sqrt{2 \times 10 \times 6.25} \\ & 5 \sqrt{5} \mathrm{~m} / \mathrm{s} \\ & v^{\prime}=\sqrt{2 \times 10 \times 0.81}=\frac{9 \sqrt{5}}{5} \mathrm{~m} / \mathrm{s} \end{aligned}\) Coefficient of restitution,…
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