AP EAMCET · PHYSICS · Kinetic Theory of Gases
When the temperature of a gas is raised from \(27^{\circ} \mathrm{C}\) to \(90^{\circ} \mathrm{C}\). The increase in the rms velocity of the gas molecules is
- A \(10 \%\)
- B \(15 \%\)
- C \(20 \%\)
- D \(17.5 \%\)
Answer & Solution
Correct Answer
(A) \(10 \%\)
Step-by-step Solution
Detailed explanation
The rms speed of the gas molecule is \(v=\sqrt{\frac{3 R T}{M}} \Rightarrow v \propto \sqrt{T}\) \(\therefore \frac{\mathrm{v}_2}{\mathrm{v}_1}=\sqrt{\frac{\mathrm{T}_2}{\mathrm{~T}_1}}=\sqrt{\frac{(273+90)}{(273+27)}}=\frac{11}{10}\) \(\therefore \%\) change in rms speed is…
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