AP EAMCET · Maths · Circle
The circles \(x^2+y^2-2 x-4 y-4=0\) and \(x^2+y^2+2 x+4 y-11=0\)
- A Cut each other orthogonally
- B do not meet
- C intersect at the points lying on the line \(4 x+8 y-7=0\)
- D touch each other at the point lying on the line \(4 x+8 y-7=0\)
Answer & Solution
Correct Answer
(C) intersect at the points lying on the line \(4 x+8 y-7=0\)
Step-by-step Solution
Detailed explanation
\((x^2+y^2-2 x-4 y-4) - (x^2+y^2+2 x+4 y-11) = 0\) \(-4x - 8y + 7 = 0\) \(4x + 8y - 7 = 0\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If the line \((2 x+3 y+4)+\lambda(6 x-y+12)=0\) is perpendicular to the line \(7 x+5 y=2\), then \(\lambda=\)AP EAMCET 2017 Easy
- The value of \(\left(\sin 210^{\circ}\right)\left(\sin 585^{\circ}\right)\) isAP EAMCET 2020 Easy
- Let \(O\) be the origin and \(A\) be a point on the curve \(y^2=4 x\). Then the locus of the mid point of \(O A\) is :AP EAMCET 2006 Medium
- The number of solutions of the equation \(\sqrt{3 x^2+x+5}=x-3\) isAP EAMCET 2025 Medium
- If \(\frac{d}{d x}\left(A \log \left(\frac{\sqrt{1-x^3}+B}{\sqrt{1-x^3}+1}\right)\right)=\frac{1}{x \sqrt{1-x^3}}\), then \(A B=\)AP EAMCET 2022 Hard
- If \(2 f(x)-3 f\left(\frac{1}{x}\right)=x+1\), then \(f^{\prime}(\sqrt{3})\) is equal toAP EAMCET 2021 Medium
More PYQs from AP EAMCET
- In the reaction \(\underset{\substack{\text { (Vapour) }}}{\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}} \underset{300^{\circ} \mathrm{C}}{\stackrel{\mathrm{Cu}}{\longrightarrow}} X\). The molecular formula of \(X\) isAP EAMCET 2005 Medium
- The product of the perpendicular distances from any point on the hyperbola \(\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\) to its asymptotes isAP EAMCET 2010 Medium
- If \(y=\cos ^{-1}\left\{\frac{a \cos x-b \sin x}{\sqrt{a^2+b^2}}\right\}\), then \(\frac{d^2 y}{d x^2}\) is equal toAP EAMCET 2021 Medium
- Calculate the mass of a photon, if its wavelength is given as \(0.35 \mathrm{~nm}\).AP EAMCET 2020 Medium
- \(f(x)\) is a quadratic polynomial satisfying the condition \(f(x)+f\left(\frac{1}{x}\right)=f(x) f\left(\frac{1}{x}\right)\). If \(f(-1)=0\), then the range of \(f\) isAP EAMCET 2025 Medium
- In Buckminster fullerene, the number of six membered carbon rings is ' \(x\) ' and five membered carbon rings is \({}^{\prime}y^{\prime},(x+y)\) value isAP EAMCET 2025 Easy