AP EAMCET · Maths · Ellipse
The major and minor axes of an ellipse are along the \(X\)-axis and \(Y\)-axis respectively. If its latusrectum is of length 4 and the distance between the foci is \(4 \sqrt{2}\), then the equation of that ellipse is
- A \(2 x^2+y^2=16\)
- B \(x^2+2 y^2=16\)
- C \(\frac{x^2}{2}+\frac{y^2}{3}=1\)
- D \(\frac{x^2}{3}+\frac{y^2}{2}=1\)
Answer & Solution
Correct Answer
(B) \(x^2+2 y^2=16\)
Step-by-step Solution
Detailed explanation
Let the equation of ellipse \(\because\) Length of latusrectum of ellipse (i) is and distance between the foci is…
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