AP EAMCET · Chemistry · Solid State
A metal oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by metal ions. The formula of metal oxide is
- A \(M O\)
- B \(M_3 \mathrm{O}_4\)
- C \(M_2 \mathrm{O}_5\)
- D \(M_2 \mathrm{O}_3\)
Answer & Solution
Correct Answer
(D) \(M_2 \mathrm{O}_3\)
Step-by-step Solution
Detailed explanation
Unit cell of hcp structure \(=6\) number of oxide ions per unit cell \(=6\) number of octahedral voids \(=6\). Since, ferric ions occupy only two out of every three octahedral voids, number of octahedral holes occupied by ferric ions \(\frac{2}{3} \times 6=4\) stoichiometric…
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