AP EAMCET · PHYSICS · Motion In One Dimension
A particle starts from rest and moves in a straight line. It travels a distance 2 L with uniform acceleration and then moves with a constant velocity a further distance of L. Finally, it comes to rest after moving a distance of 3L under uniform retardation. Then the ratio of average speed to the maximum speed \(\left(\frac{\bar{V}}{V_m}\right)\) of the particle is
- A \(\frac{6}{11}\)
- B \(\frac{7}{11}\)
- C \(\frac{5}{11}\)
- D \(\frac{2}{11}\)
Answer & Solution
Correct Answer
(A) \(\frac{6}{11}\)
Step-by-step Solution
Detailed explanation
The \(v\)-t graph of the particle is \(\begin{aligned} & 2 L=\frac{1}{2} v_{\max } \times t_1 \Rightarrow t_1=\frac{4 L}{v_{\max }} \\ & L=v_{\max } \times t_2 \Rightarrow t_2=\frac{L}{v_{\max }}\end{aligned}\)…
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