AP EAMCET · PHYSICS · Magnetic Effects of Current
A charged particle when enters a uniform magnetic field moves in a helical path. If its angular velócity is \(4 \pi \times 10^6\) rads \(^{-1}\) and its velocity in the direction of magnetic field is \(3 \times 10^5 \mathrm{~ms}^{-1}\) then the pitch of the helix is
- A \(5 \mathrm{~cm}\)
- B \(10 \mathrm{~cm}\)
- C \(15 \mathrm{~cm}\)
- D \(20 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(C) \(15 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Angular velocity, \(\omega=4 \pi \times 10^6 \mathrm{rad} / \mathrm{s}\) Velocity of changes particle, \(v=3 \times 10^5 \mathrm{~m} / \mathrm{s}\) Pitch of the helix \(=\mathrm{v} \times \mathrm{t}\) \(=3 \times 10^5 \times \frac{2 \pi}{\omega}\)…
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