AP EAMCET · Maths · Circle
Suppose the tangents drawn to the circle \(x^2+y^2-6 x-4 y-11=0\) from \(P(1,8)\) touch the circle at \(A\) and \(B\). Then the centre of the circle passing through \(P\), \(\mathrm{A}\) and \(\mathrm{B}\) is
- A \((2,5)\)
- B \((-2,-5)\)
- C \((-2,5)\)
- D \((2,-5)\)
Answer & Solution
Correct Answer
(A) \((2,5)\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \(x^2+y^2-6 x-4 y-11=0\) \[ \therefore \text { centre }=(3,2) \] A circle passing through \(\mathrm{P}, \mathrm{A}\) and \(\mathrm{B}\) then \(\mathrm{PC}\) is a diameter \(\therefore\) centre of required circle is…
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