AP EAMCET · PHYSICS · Oscillations
A particle is executing SHM. The time taken for \(\left(\frac{3}{8}\right)^{\text {th }}\) of oscillation from extreme positions is \(x\). Then, the time taken for the particle to complete \(\left(\frac{5}{8}\right)^{\text {th }}\) of oscillation from mean position is
- A \(\frac{5 x}{4}\)
- B \(\frac{7 x}{4}\)
- C \(\frac{21 x}{8}\)
- D \(\frac{7 x}{12}\)
Answer & Solution
Correct Answer
(B) \(\frac{7 x}{4}\)
Step-by-step Solution
Detailed explanation
We divide total distance \(4 A\) in 8 equal parts. So, for a displacement of \(\frac{3}{8}\) th of an oscillation from an extreme, Time \(=\frac{T}{6}+\frac{T}{12}+\frac{T}{12}=\frac{2+1+1}{12} T=\frac{4}{12} T=\frac{T}{3}\) Given, \(\frac{T}{3}=x\) or \(T=3 x\) Now, for…
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