AP EAMCET · Maths · Continuity and Differentiability
If a function \(\mathrm{f}(\mathrm{x})\) defined by
\(f(x)=\left\{\begin{array}{c}a x^2+b x+c, x \leq-1 \\ 2 x^2+4 x+1,-1 < x < 1 \\ c x^2+b x+a, x \geq 1\end{array}\right.\)
is continuous on \(\mathbb{R}\), and \(\lim _{x \rightarrow \frac{3}{2}} f(x)=14\), then
\(\lim _{x \rightarrow-2} f(x)=\quad x \rightarrow \frac{3}{2}\)
- A 6
- B -8
- C 5
- D 1
Answer & Solution
Correct Answer
(B) -8
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow \frac{3}{2}} f(x)=14 \Rightarrow\) C. \(\frac{9}{4}+\frac{3 b}{2}+a=14\) \(\Rightarrow 9 c+6 b+4 a=56\) ...(i) Right hand limit at \(x=-1=f(-1)\)…
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