AP EAMCET · PHYSICS · Electromagnetic Induction
A metal \(\operatorname{rod} A B\) of length \(50 \mathrm{~cm}\) is moving at a velocity \(8 \mathrm{~ms}^{-1}\) in a magnetic field of \(2 \mathrm{~T}\). If the field is at \(60^{\circ}\) with the plane of motion as shown in the figure, then the potentials \(V_A\) and \(V_B\) are related by
- A \(V_A-V_B=8 \mathrm{~V}\)
- B \(V_A-V_B=4 \mathrm{~V}\)
- C \(V_B-V_A=8 \mathrm{~V}\)
- D \(V_B-V_A=4 \mathrm{~V}\)
Answer & Solution
Correct Answer
(B) \(V_A-V_B=4 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
A metal rod \(A B\) shown in the figure moves with speed \(8 \mathrm{~ms}^{-1}\). As the emf induced in the metal rod,…
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