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AP EAMCET · Chemistry · Structure of Atom

The wavenumber of the first line \(\left(n_2=3\right)\) in the Balmer series of hydrogen is \(\overline{\mathrm{v}}_1 \mathrm{~cm}^{-1}\). What is the wavenumber (in \(\mathrm{cm}^{-1}\) ) of the second line ( \(\mathrm{n}_2=4\) ) in the Balmer series of \(\mathrm{He}^{+}\)?

  1. A \(\frac{5 \bar{v}_1}{27}\)
  2. B \(\frac{27 \bar{v}_1}{5}\)
  3. C \(\frac{27 \bar{v}_1}{20}\)
  4. D \(\frac{20 \bar{v}_1}{27}\)
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Correct Answer

(B) \(\frac{27 \bar{v}_1}{5}\)

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