AP EAMCET · Chemistry · Structure of Atom
The wavenumber of the first line \(\left(n_2=3\right)\) in the Balmer series of hydrogen is \(\overline{\mathrm{v}}_1 \mathrm{~cm}^{-1}\). What is the wavenumber (in \(\mathrm{cm}^{-1}\) ) of the second line ( \(\mathrm{n}_2=4\) ) in the Balmer series of \(\mathrm{He}^{+}\)?
- A \(\frac{5 \bar{v}_1}{27}\)
- B \(\frac{27 \bar{v}_1}{5}\)
- C \(\frac{27 \bar{v}_1}{20}\)
- D \(\frac{20 \bar{v}_1}{27}\)
Answer & Solution
Correct Answer
(B) \(\frac{27 \bar{v}_1}{5}\)
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