AP EAMCET · PHYSICS · Waves and Sound
On producing the waves of frequency \(1000 \mathrm{~Hz}\) in a Kundt's tube, the total distance between 6 successive nodes is \(85 \mathrm{~cm}\). Then, the speed of sound in the gas filled in the tube is
- A \(330 \mathrm{~ms}^{-1}\)
- B \(340 \mathrm{~ms}^{-1}\)
- C \(350 \mathrm{~ms}^{-1}\)
- D \(300 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(B) \(340 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Frequency, \(f=1000 \mathrm{~Hz}\) Total distance between 6 successive nodes \(d=85 \mathrm{~cm}=0.85 \mathrm{~m}\) Since, distance between 6 successive nodes is equivalent to \(2 \lambda+\frac{\lambda}{2}=\frac{5 \lambda}{2}\)…
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