AP EAMCET · PHYSICS · Motion In Two Dimensions
A gun and a target are at the same horizontal level separated by a distance of \(600 \mathrm{~m}\). The bullet is fired from the gun with a velocity of \(500 \mathrm{~ms}^{-1}\). In order to hit the target, the gun should be aimed to a height \(h\) above the target. The value of \(h\) is (Acceleration due to gravity, \(g=10 \mathrm{~ms}^{-2}\) )
- A \(2.4 \mathrm{~m}\)
- B \(3.6 \mathrm{~m}\)
- C \(7.2 \mathrm{~m}\)
- D \(10.8 \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(7.2 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Given, distance between gun and target \(=600 \mathrm{~m}\) velocity of bullet \(=500 \mathrm{~ms}^{-1}\) Now, distance \(=\) velocity of bullet \(\times\) time \(\begin{gathered} 600=500 \times t \\ t=\frac{600}{500}=\frac{6}{5}=1.2 \mathrm{sec} \end{gathered}\) From second…
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