AP EAMCET · PHYSICS · Electrostatics
The electric field due to a short electric dipole at a distance \(r\) on the axial line from its mid-point is \(x\) times the electric field at a distance \(2 r\) on the equatorial line from the mid-point of dipole. Then, the value of \(x\) is
- A 16
- B 9
- C 25
- D 36
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
On axis, field magnitude, \(E_1=\frac{2 k p}{r^3}\) On equatorial axis, field magnitude \( E_2=\frac{k p}{(2 r)^3}=\frac{k p}{8 r^3} \) So, \( E_1=16 E_2 \Rightarrow x=16 \)
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