AP EAMCET · PHYSICS · Dual Nature of Matter
A point source of electromagnetic radiation has an average power output of \(960 \mathrm{~W}\). The peak value of the electric field at a distance \(400 \mathrm{~cm}\) from the source is
- A \(60 \mathrm{Vm}^{-1}\)
- B \(120 \mathrm{Vm}^{-1}\)
- C \(30 \mathrm{Vm}^{-1}\)
- D \(180 \mathrm{Vm}^{-1}\)
Answer & Solution
Correct Answer
(A) \(60 \mathrm{Vm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, average power output, \(P=960 \mathrm{~W}\) Distance, \(r=400 \mathrm{~cm}=4 \mathrm{~m}\) Intensity of \(E M\) waves is given by…
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