AP EAMCET · PHYSICS · Kinetic Theory of Gases
A diatomic gas consisting of rigid molecules is at a temperature of \(87^{\circ} \mathrm{C}\). If the moment of inertia of the rotating diatomic rigid molecule is \(2.76 \times 10^{-39} \mathrm{gcm}^2\), then the rms angular speed of the molecule is (Boltzmann constant \(=1.38 \times 10^{-23} \mathrm{JK}^{-1}\) )
- A \(6 \times 10^{12}\) rads \(^{-1}\)
- B \(3 \times 10^{12} \mathrm{rads}^{-1}\)
- C \(6 \times 10^{13} \mathrm{rads}^{-1}\)
- D \(3 \times 10^{13}\) rads \(^{-1}\)
Answer & Solution
Correct Answer
(A) \(6 \times 10^{12}\) rads \(^{-1}\)
Step-by-step Solution
Detailed explanation
Moment of inertia of diatomic molecule, \(I=\frac{2}{3} M r^2\) So, radius, \(r=\sqrt{\frac{3 I}{2 M}}\) ...(i) rms speed of molecule, \(v=\sqrt{\frac{3 k T}{M}}\) rms angular speed,…
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