AP EAMCET · Chemistry · Some Basic Concepts of Chemistry

$0.63 g$ of Oxalic acid is dissolved in order to obtain $250 {cm}^{3}$ of its solution. Find the normality of this solution. [Oxalic acid: $(COOH)_{2} \cdot 2 H_{2} O]$

A $0.05 N$
B $0.01 N$
C $0.04 N$
D $0.02 N$

Verified Solution

Answer & Solution

Correct Answer

(C) $0.04 N$

Step-by-step Solution

Detailed explanation

Molar mass of oxalic acid = 126 g/mol Mole =Given massMolar mass=0.63126=0.005 mol Molarity = Mole of soluteVolume of solution in ml×1000=0.005250×1000=0.02M Equivalent mass of oxalic acid = 1262=63 Gram equivalent of…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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0.63 g of Oxalic acid is dissolved in order to obtain 250 cm3 of its solution. Find the normality of this solution. [Oxalic acid: (COOH)2·2H2O

Step-by-step Solution

$0.63 g$ of Oxalic acid is dissolved in order to obtain $250 {cm}^{3}$ of its solution. Find the normality of this solution. [Oxalic acid: $(COOH)_{2} \cdot 2 H_{2} O]$