AP EAMCET · Maths · Binomial Theorem
If \(\alpha=\frac{5}{2 ! \times 3}+\frac{5 \times 7}{3 ! \times 3^2}+\frac{5 \times 7 \times 9}{4 ! \times 3^3}+\ldots .\), then \(\alpha^2+4 \alpha=\)
- A 21
- B 23
- C 25
- D 27
Answer & Solution
Correct Answer
(B) 23
Step-by-step Solution
Detailed explanation
Since, \[ \begin{aligned} (1+x)^n=1+n x+ & \frac{n(n-1)}{2 !} x^2+\frac{n(n-1)(n-2)}{3 !} x^3 \\ & +\frac{n(n-1)(n-2)(n-3)}{4 !} x^4+\ldots \end{aligned} \] On comparing \(\frac{n(n-1)}{2 !} x^2=\frac{5}{2 ! \times 3}\) and…
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