AP EAMCET · PHYSICS · Magnetic Effects of Current
A current carrying coil experiences a torque due to a magnetic field. The value of the torque is \(80 \%\) of the maximum possible torque. The angle between the magnetic field and the normal to the plane of the coil is
- A \(30^{\circ}\)
- B \(45^{\circ}\)
- C \(\tan ^{-1}\left(\frac{3}{4}\right)\)
- D \(\tan ^{-1}\left(\frac{4}{3}\right)\)
Answer & Solution
Correct Answer
(D) \(\tan ^{-1}\left(\frac{4}{3}\right)\)
Step-by-step Solution
Detailed explanation
the torque experience by a current carrying coil in a magnetic field is \(\mathrm{l}=\mathrm{MB} \sin \theta \Rightarrow \mathrm{t}_{\max }=\mathrm{MB}\) Also, \(\mathrm{l}=80 \%\) of \(\mathrm{i}_{\max }=\frac{4}{5} \mathrm{t}_{\max }=\frac{4}{5} \mathrm{MB}\)…
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