AP EAMCET · PHYSICS · Motion In One Dimension
A body projected from the ground reaches a point \(X\) in its path after 3 seconds and from there it reaches the ground after further 6 seconds. The vertical distance of the point \(X\) from the ground is (acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(30\ m\)
- B \(60\ m\)
- C \(80\ m\)
- D \(90\ m\)
Answer & Solution
Correct Answer
(D) \(90\ m\)
Step-by-step Solution
Detailed explanation
Total time of flight \((t)=\frac{2 u}{g}\) or, \(9=\frac{2 u}{g} \quad\) or, \(u=\frac{9 g}{2}\) or, \(\quad u=\frac{9 \times 10}{2}\) or, \(u=45 \mathrm{~m} / \mathrm{s}\) Since, in covering the vertical distance, \(g\) becomes - (ve)…
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