AP EAMCET · PHYSICS · Electrostatics
Two particles of equal mass ' \(m\) ' and equal charge ' \(q\) ' are separated by a distance of 16 cm . They do not experience any force. The value of \(\frac{q}{m}\) is _____ (if ' \(G\) ' is the universal gravitational constant and ' \(g\) ' is the acceleration due to gravity).
- A \(\sqrt{4 \pi \epsilon_0 \mathrm{G}}\)
- B \(\sqrt{\frac{G}{4 \pi \epsilon_0}}\)
- C \(\sqrt{\frac{\pi \epsilon_0}{\mathrm{G}}}\)
- D \(\sqrt{4 \pi \epsilon_0 g}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{4 \pi \epsilon_0 \mathrm{G}}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {At equilibrium, } \mathrm{F}_{\mathrm{g}}=\mathrm{F}_{\mathrm{e}} \\ & \Rightarrow \frac{\mathrm{Gm}^2}{(16)^2}=\frac{\mathrm{kq}^2}{(16)^2} \\ &…
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