AP EAMCET · PHYSICS · Waves and Sound
A closed organ pipe of length ' \(L\) ' and an open organ pipe contain gases of densities \(\rho_1\) and \(\rho_2\) respectively. The compressibility of gases are equal in both the pipes. If the frequencies of their first overtones are same, then the length of the open organ pipe is
- A \(\frac{4 L}{3} \sqrt{\frac{\rho_2}{\rho_1}}\)
- B \(\frac{4 L}{3} \sqrt{\frac{\rho_1}{\rho_2}}\)
- C \(\frac{4 L}{3}\)
- D \(\frac{L}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{4 L}{3} \sqrt{\frac{\rho_1}{\rho_2}}\)
Step-by-step Solution
Detailed explanation
For closed organ pipe, Ist overtone \(=3 \mathrm{rd}\) harmonic \[ f=f_2=3 f_1=\frac{3 \times v}{4 L}=\frac{3}{4 L} \times \sqrt{\frac{\gamma p}{\rho_1}} \] For open organ pipe, Ist overtone \(=2 \mathrm{nd}\) harmonics…
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