AP EAMCET · PHYSICS · Electrostatics
An infinite number of electric charges each equal to 5 nano-coulomb (magnitude) are placed along \(X\)-axis at \(x=1 \mathrm{~cm}, x=2 \mathrm{~cm}\), \(x=4 \mathrm{~cm}, x=8 \mathrm{~cm} . . .\). and so on. In this set up if the consecutive charges have opposite sign, then the electric field in newton/coulomb at \(x=0\) is :
\(\left(\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N}-\mathrm{m}^2 / \mathrm{C}^2\right)\)
- A \(12 \times 10^4\)
- B \(24 \times 10^4\)
- C \(36 \times 10^4\)
- D \(48 \times 10^4\)
Answer & Solution
Correct Answer
(C) \(36 \times 10^4\)
Step-by-step Solution
Detailed explanation
Electric field intensity due to a point charge. \(E=\frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q}{r^2}\) The consecutive charges are of opposite signs. \(\therefore\) Net electric field at \(x=0\), is…
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