AP EAMCET · PHYSICS · Ray Optics
The angle of polarisation for a medium with respect to air is \(60^{\circ}\). The critical angle of this medium with respect to air is
- A \(\sin ^{-1} \sqrt{3}\)
- B \(\tan ^{-1} \sqrt{3}\)
- C \(\cos ^{-1} \sqrt{3}\)
- D \(\sin ^{-1} \frac{1}{\sqrt{3}}\)
Answer & Solution
Correct Answer
(D) \(\sin ^{-1} \frac{1}{\sqrt{3}}\)
Step-by-step Solution
Detailed explanation
Angle of polarisation, \(\mathrm{i}_{\mathrm{p}}=60^{\circ}\) \(\therefore \quad \mu=\tan \mathrm{i}_{\mathrm{p}}=\tan 60^{\circ}=\sqrt{3}\) \(\therefore \quad\) Critical angle, \(C=\sin ^{-1}\left(\frac{1}{\mu}\right)=\sin ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
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