AP EAMCET · Chemistry · Coordination Compounds
A coordination compound is made of \(\mathrm{Co}^{3+}\), \(\mathrm{NH}_3\), and \(\mathrm{Cl}^{-}, 0.1 \mathrm{M}\) solution of this complex when treated with excess silver nitrate gave no precipitate. The formula of the complex and secondary valency of metal are respectively.
- A \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right], 6\)
- B \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3 \mathrm{Cl}_2, 6\right.\)
- C \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right], 3\)
- D \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}, 6\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_3 \mathrm{Cl}_3\right], 6\)
Step-by-step Solution
Detailed explanation
Since, no precipitate of \(\mathrm{AgCl}\) is obtained on treating the compound with silver nitrate that means no \(\mathrm{Cl}^{-}\)ions are available outside the coordination sphere. So, correct formula of coordination compound is…
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