AP EAMCET · PHYSICS · Motion In One Dimension
Two bodies of masses ' \(\mathrm{m}_1{ }^{\prime}\) and ' \(\mathrm{m}_2\) ' are dropped from two different heights \(h_1\) and \(h_2\) respectively. The ratio of the times taken by the two masses to touch the ground is (neglect air resistance)
- A \(\frac{\mathrm{h}_1}{\mathrm{~h}_2}\)
- B \(\frac{m_1 h_1}{m_2 h_2}\)
- C \(\frac{\mathrm{m}_1 \mathrm{~h}_2}{\mathrm{~m}_2 \mathrm{~h}_1}\)
- D \(\sqrt{\frac{\mathrm{h}_1}{\mathrm{~h}_2}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{\mathrm{h}_1}{\mathrm{~h}_2}}\)
Step-by-step Solution
Detailed explanation
from the equation of motion…
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