AP EAMCET · PHYSICS · Waves and Sound
A car sounding a horn of frequency 1000 Hz passes a stationary observer. The ratio of frequencies of the horn noted by the observer before and after passing of the car is \(11: 9\). The speed of car is (Speed of sound \(v=340 \mathrm{~ms}^{-1}\) )
- A \(34 \mathrm{~ms}^{-1}\)
- B \(17 \mathrm{~ms}^{-1}\)
- C \(170 \mathrm{~ms}^{-1}\)
- D \(340 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(34 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{f}=1000 \mathrm{~Hz}\) When the car approaching the observer, \(f_1=\left(\frac{v}{v-v_s}\right) f\) When the car moving away from the observer,…
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