AP EAMCET · PHYSICS · Mechanical Properties of Fluids
Water flows through a hose pipe whose internal diameter is \(4 \mathrm{~cm}\) at a speed of \(1 \mathrm{~ms}^{-1}\). If water has to emerge at a speed of \(4 \mathrm{~ms}^{-1}\), then the diameter of the nozzle should be
- A \(1 \mathrm{~cm}\)
- B \(2 \mathrm{~cm}\)
- C \(4 \mathrm{~cm}\)
- D \(0.5 \mathrm{~cm}\)
Answer & Solution
Correct Answer
(B) \(2 \mathrm{~cm}\)
Step-by-step Solution
Detailed explanation
Internal diameter for hose pipe, \(d_1=4 \mathrm{~cm}, r_1=\frac{d}{2}=\frac{4}{2}=2 \mathrm{~cm}=2 \times 10^{-2} \mathrm{~m}\) Speed of water through hose pipe, \(v_1=1 \mathrm{~ms}^{-1}\) Speed of water through nozzle, \(v_2=4 \mathrm{~ms}^{-1}\) Diameter, \(d_2=\) ?…
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