AP EAMCET · Chemistry · Thermodynamics (C)

Two flasks $A$ and $B$ have equal volumes. $A$ is maintained at $300 K$ and $B$ at $600 K$ . Equal masses of $H_{2}$ and ${CO}_{2}$ are taken in flasks $A$ and $B$ respectively. Find the ratio of total $K . E$ of gases in flask $A$ to that of $B$ .

A $1 : 2$
B $11 : 1$
C $33 : 2$
D $55 : 7$

Verified Solution

Answer & Solution

Correct Answer

(B) $11 : 1$

Step-by-step Solution

Detailed explanation

We know that the average kinetic energy depends on the temperature and number of moles. Now, K.E. expression for flasks A and B is given below: K.E.A=3nART A2 K.E.B=3nBRTB2 Assume common mass=m nA=m/2nB=m/44…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Two flasks A and B have equal volumes. A is maintained at 300 K and B at 600 K. Equal masses of H2 and CO2 are taken in flasks A and B respectively. Find the ratio of total K.E of gases in flask A to that of B.

Step-by-step Solution

Two flasks $A$ and $B$ have equal volumes. $A$ is maintained at $300 K$ and $B$ at $600 K$ . Equal masses of $H_{2}$ and ${CO}_{2}$ are taken in flasks $A$ and $B$ respectively. Find the ratio of total $K . E$ of gases in flask $A$ to that of $B$ .