AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
A bullet of mass \(m\) and velocity \(v\) when fired at a sand bag of mass \(M\), suspended by a string, gets embedded into the bag. The loss of kinetic energy in this process is
- A \(\frac{m v^2}{2}\)
- B \(\frac{m v^2}{2(M+m)}\)
- C \(\frac{M v^2}{2}\)
- D \(\frac{m M N^2}{2(M+m)}\)
Answer & Solution
Correct Answer
(D) \(\frac{m M N^2}{2(M+m)}\)
Step-by-step Solution
Detailed explanation
Mass of the buIlet \(=m\) Speed of bullet \(=v\) According to question, bullets gets embedded into the bag, then they will move with common velocity \(v_1\) (say). This is the case of perfectly enelastic collision. \(\therefore\) Initial kinetic energy of bullet,…
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