AP EAMCET · PHYSICS · Mechanical Properties of Solids
A wire is stretched 1 mm by a force \(F\). If a second wire of same material, same length and 4 times the diameter of the first wire is stretched by the same force \(F\), then the elongation of the second wire is
- A \(\frac{1}{8} \mathrm{~mm}\)
- B 8 mm
- C 16 mm
- D \(\frac{1}{16} \mathrm{~mm}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{16} \mathrm{~mm}\)
Step-by-step Solution
Detailed explanation
\(\Delta L = \frac{FL}{AY}\) \(A_2 = \pi (\frac{d_2}{2})^2 = \pi (\frac{4d_1}{2})^2 = 16 \pi (\frac{d_1}{2})^2 = 16A_1\) \(\Delta L_2 = \frac{FL}{A_2 Y} = \frac{FL}{(16A_1)Y} = \frac{1}{16} \left( \frac{FL}{A_1 Y} \right) = \frac{1}{16} \Delta L_1\)…
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