AP EAMCET · Maths · Circle
Find the equation of a circle which cuts the circle \(x^2+y^2-6 x+4 y-3=0\) orthogonally, while passing through \((3,0)\) and touching the \(Y\)-axis.
- A \(x^2+y^2+6 x+6 y+9=0\)
- B \(x^2+y^2-6 x-6 y+9=0\)
- C \(x^2+y^2-6 x+6 y-9=0\)
- D \(x^2+y^2+6 x-6 y-9=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-6 x-6 y+9=0\)
Step-by-step Solution
Detailed explanation
When two circles intersects each other orthogonally, then \(2\left(g_1 g_2+f_1 f_2\right)=c_1 c_2\), where two circles are \(\begin{aligned} & x^2+y^2+2 g_1 x+2 f_1 y+c_1=0 \text { and } \\ & x^2+y^2+2 g_2 x+2 f_2 y+c_2=0 \end{aligned}\) Let \(c(h, k)\) be the centre of required…
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