AP EAMCET · PHYSICS · Motion In One Dimension
The velocity of an object moving in a straight line path is given as a function of time by \(v=6 t-3 t^2\), where \(v\) is in \(\mathrm{ms}^{-1}, t\) is in \(\mathrm{s}\). The average velocity of the object between, \(t=0\) and \(t=2 \mathrm{~s}\) is
- A 0
- B \(3 \mathrm{~ms}^{-1}\)
- C \(2 \mathrm{~ms}^{-1}\)
- D \(4 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(C) \(2 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, velocity, \(v=6 t-3 t^2\) As we know that, \(v=\frac{d x}{d t}\) Here, \(x\) is the displacement of the particle. Now, \(d x=v d t\) Integrate on the both sides, limit \(t=0\) to \(t=2\), we get…
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