AP EAMCET · PHYSICS · Mathematics in Physics
When two resistors of resistances \(R_1=(200 \pm 2) \Omega\) and \(R_2=(400 \pm 4) \Omega\) are connected in series, then the equivalent resistance of the combination is
- A \((800 \pm 7) \Omega\)
- B \((600 \pm 2) \Omega\)
- C \((600 \pm 6) \Omega\)
- D \((200 \pm 2) \Omega\)
Answer & Solution
Correct Answer
(C) \((600 \pm 6) \Omega\)
Step-by-step Solution
Detailed explanation
Given, \(R_1=(200 \pm 2) \Omega\) \(R_2=(400 \pm 4) \Omega\) \(\begin{aligned} & \text {Resistance in series, } R_s=R_1+R_2 \\ & \Rightarrow \quad=(200 \pm 2)+(400 \pm 4) \Omega \\ & \Rightarrow \quad R_s=(600 \pm 6) \Omega \end{aligned}\)
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