AP EAMCET · Maths · Properties of Triangles
In \(\triangle \mathrm{ABC}\), if \(\angle \mathrm{C}=90^{\circ}\), then \(\left(\frac{\mathrm{r}_1-\mathrm{r}_3}{\mathrm{r}_1}\right)\left(\frac{\mathrm{r}_2-\mathrm{r}_3}{\mathrm{r}_2}\right)=\)
- A \(1\)
- B \(3\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text {} \because \angle C=90^{\circ} \Rightarrow C^2=a^2+b^2 \\ & \text { Now, }\left(\frac{r_1-r_3}{r_1}\right)\left(\frac{r_2-r_3}{r_2}\right)=\frac{\frac{\Delta}{s-a}-\frac{\Delta}{s-c}}{\frac{\Delta}{s-a}} \cdot…
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