AP EAMCET · PHYSICS · Thermal Properties of Matter
A body cools down from \(52.5^{\circ} \mathrm{C}\) to \(47.5^{\circ} \mathrm{C}\) in \(5 \mathrm{~min}\) and from \(47.5^{\circ} \mathrm{C}\) to \(42.5^{\circ} \mathrm{C}\) in \(7.5 \mathrm{~min}\). Then, the temperature of the surroundings is
- A \(39^{\circ} \mathrm{C}\)
- B \(25^{\circ} \mathrm{C}\)
- C \(35^{\circ} \mathrm{C}\)
- D \(15^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(35^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given that, for first condition, Initial temperature, \(T_1=52.5^{\circ} \mathrm{C}\) Final temperature, \(T_2=47.5^{\circ} \mathrm{C}\) Average temperature, \(T_{\mathrm{av}}=\frac{T_1+T_2}{2}\) \[ =\frac{525+47.5}{2}=50^{\circ} \mathrm{C} \] For second condition, Initial…
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