AP EAMCET · Maths · Parabola
The tangents to the parabola \(y^2=4 a x\) from an external point \(P\) make angles \(\theta_1\) and \(\theta_2\) with the axis of the parabola. Such that \(\tan \theta_1+\tan \theta_2=b\), where \(b\) is constant. Then \(P\) lies on
- A \(y=x+b\)
- B \(y+x=b\)
- C \(y=\frac{x}{b}\)
- D \(y=b x\)
Answer & Solution
Correct Answer
(D) \(y=b x\)
Step-by-step Solution
Detailed explanation
Here, \(P\) is intersecting point of tangents at \[ \begin{gathered} A\left(a t_1^2, 2 a t_1\right) \text { and } B\left(a t_2^2, 2 a t_2\right) \\ P\left(a t_1 t_2 a\left(t_1 t_2\right)\right. \end{gathered} \] Slope of line \(P A\)…
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