AP EAMCET · PHYSICS · Electromagnetic Induction
A coil of wire of radius \(r\) has 600 turns and self inductance of \(108 \mathrm{mH}\). The self inductance of a coil with same radius and 500 turns is
- A 80 mH
- B 75 mH
- C 108 mH
- D 90 mH
Answer & Solution
Correct Answer
(D) 90 mH
Step-by-step Solution
Detailed explanation
Self-inductance of a coil \(=\frac{N \phi_B}{I}\) \[ =\frac{N \frac{\mu_0 I}{2 R} \times \pi R^2}{I}=\frac{\pi \mu_0}{2} \cdot N R \] So,…
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