AP EAMCET · PHYSICS · Work Power Energy
A block of mass \(2 \mathrm{~kg}\) is pulled at a constant speed with a taut rope along a frictionless plane that is inclined at \(30^{\circ}\). Then the work done by the tension in the rope in pulling it a distance \(4 \mathrm{~m}\) along the inclined plane in joule is
\(\left(\right.\) acceleration due to gravity \(=10 \mathrm{~ms}^{-2}\) )
- A \(40\)
- B \(20\)
- C \(68\)
- D \(136\)
Answer & Solution
Correct Answer
(A) \(40\)
Step-by-step Solution
Detailed explanation
As \(V=\) constant \(\begin{aligned} & \Rightarrow \mathrm{T}=\mathrm{mg} \sin \theta \\ & \Rightarrow \mathrm{T}=2 \times 10 \times \sin 30^{\circ} \\ & \Rightarrow \mathrm{T}=10 \mathrm{~N}\end{aligned}\) So, work done \(=\mathrm{T} \times \mathrm{x}\)…
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