AP EAMCET · PHYSICS · Magnetic Effects of Current
A beam of protons enters a uniform magnetic field of \(0.314 \mathrm{~T}\) with a velocity \(4 \times 10^5 \mathrm{~ms}^{-1}\) in a direction making an angle \(60^{\circ}\) with the direction of the magnetic field.The path of the beam is (mass of proton \(\left.=1.6 \times 10^{-27} \mathrm{~kg}\right)\)
- A a circle of radius 0.2 m
- B a straight line
- C a helix with a pitch 4 cm
- D a helix with a pitch 4 mm
Answer & Solution
Correct Answer
(C) a helix with a pitch 4 cm
Step-by-step Solution
Detailed explanation
As, \(\mathbf{v}\) is not perpendicular to \(\mathbf{B}\), so path of particle is helix.…
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