AP EAMCET · Maths · Probability
Two dice are thrown and the sum of the numbers appeared on the dice is noted. If \(A\) is the event of getting a prime number as their sum and \(B\) is the event of getting a number greater than 8 as their sum, then \(\mathrm{P}(\mathrm{A} \cap \overline{\mathrm{B}})=\)
- A \(\frac{1}{4}\)
- B \(\frac{13}{36}\)
- C \(\frac{2}{9}\)
- D \(\frac{5}{18}\)
Answer & Solution
Correct Answer
(B) \(\frac{13}{36}\)
Step-by-step Solution
Detailed explanation
Total outcomes: \( 6^2 = 36 \). Sums for \( A \) (prime): \( \{2,3,5,7,11\} \). Sums for \( \overline{B} \) (not \( > 8 \)): \( \{2,3,4,5,6,7,8\} \). Favorable sums for \( A \cap \overline{B} \): \( \{2,3,5,7\} \).…
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