AP EAMCET · PHYSICS · Work Power Energy
A body is projected vertically upwards with a velocity of \(20 \mathrm{~m} \mathrm{~s}^{-1}\). If the potential energy of the body at a height of 5 m from the ground is 100 J, then the kinetic energy of the body at a height of 10 m from the ground is
(Acceleration due to gravity \(=10 \mathrm{~m} \mathrm{~s}^{-2}\) )
- A 200 J
- B 300 J
- C 150 J
- D 250 J
Answer & Solution
Correct Answer
(A) 200 J
Step-by-step Solution
Detailed explanation
\(m = \frac{\mathrm{PE}}{gh} = \frac{100 \mathrm{~J}}{10 \mathrm{~m} \mathrm{~s}^{-2} \times 5 \mathrm{~m}} = 2 \mathrm{~kg}\) \(\mathrm{E_{total}} = \frac{1}{2}mu^2 + mgh_{initial} = \frac{1}{2}(2 \mathrm{~kg})(20 \mathrm{~m} \mathrm{~s}^{-1})^2 + 0 = 400 \mathrm{~J}\)…
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