AP EAMCET · PHYSICS · Laws of Motion
A 4kg mass is suspended as shown in figure. All pulleys are frictionless and spring constant K is \(8 \times 10^3 \mathrm{Nm}^{-1}\) The extension in spring is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
- A 2 mm
- B 2 cm
- C 4 cm
- D 4 mm
Answer & Solution
Correct Answer
(B) 2 cm
Step-by-step Solution
Detailed explanation
\(\mathrm{k}=8 \times 10^3 \mathrm{Nm}^{-1}\) From figure, \(T=40 \mathrm{~N} \Rightarrow\) Force in spring, \(\mathrm{F}=4 \mathrm{~T}=160 \mathrm{~N}\) \(\therefore\) Extension in the spring, \(x=\frac{F}{K}=\frac{160}{8 \times 10^3}=2 \mathrm{~cm}\)
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